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Calculate the mean free path of air molecules at a pressure of 4.50×10−13 atm and a...

Calculate the mean free path of air molecules at a pressure of 4.50×10−13 atm and a temperature of 292 K. (This pressure is readily attainable in the laboratory.) Model the air molecules as spheres with a radius of 2.00×10−10 m.

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Answer #1

RT 12 T INP d=29= 212X510) = 4x100 P = 54.5X103 (101325) - 4.559625 x 108 pa 8.314 (292) 12.11 ( 4 xūlo)! 76.0227133) (4 5396

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