Question

QUESTION 1 239 a) (15p) We consider a nuclear reactor of power output P-1000 Megawatt (1000 million watts) electric functioning with Plutonium. It is fueled, initially, with 1000 kg of Plutonium. The nuclear material in question is made of Plutonium nuclei, each consisting in 94 protons and rd 239-94-145 neutrons, which is denominated by the symbol 94 Pu For thermodynamical reasons, only 1/3 of the nuclear energy in the form of heat produced by the reactor, can be converted into electricity. How much mass deficit Am should the nuclear fuel of concem 2 delineates, if the reactor is operated through a period of At 2 years. You are supposed to use Einstein's relationship AEC Am (where is the velocity of light in vacuum, i.e. about 300 000 km/s). Note further that the reactor power, by definition, is given by AE/At. Make sure that you use coherent units b) (10p) How much mass deficit between the reactants (C+02) and the reaction products (CO2), all weighed at rest, would delineate a coal (C) thermal plant of the same capacity, working under the same thermodynamical regime, through the same period of 2 years of operation ho which needs to burn about 3 millions coal per year? Attach File Browse My Computer Browse Content Collection

Answer 1

1)

P=10^(9) W

$\bigtriangleup t=2years=2\times 365\times 24\times 3600=93072000 s$

$P=\frac{\Delta E}{\Delta t} \therefore \Delta E=P\Delta t=6.3072\times 10^{16}J$

since, $\Delta E=\Delta m\times C^{2} \therefore \Delta m=0.7008 Kg$

2)

$\Delta m=(Zm_{p}+Nm_{n})_{reactant}-m_{product}$

Z=6(proton of carbon)+2*8(proton of oxygen)=22

N=6(neutron of carbon)+2*8(neutron of oxygen)=22

Ξ 44.3509μ – 44.0094μ Δm 22 x (1.00728 + 1.00867) – 44.0094μ 0.3415μ = 5.670949 x 1024Kg

3)In Question 3 it has't mentioned what we have to find out.

PLEASE HIT THE LIKE BUTTON IF YOU LIKE THE ANSWER BECAUSE IT TAKES A LOT OF EFFORT TO ANSWER .KEEP STUDYING, KEEP ASKING. THANK YOU.