Question 2. A truss structure is shown in Figure 2. Consider points A and F have...

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3 KN 8 m C DE lºr Moje 5 m 10 m 5 m 1 m 1m RA RE Efy = 0 => RA+ Rp = 3 KM ZMA=0 Rf(22) – 3(11) = 0 RE= 1.5KN RA = 1.5kn Secti MH = 0 FIH and FH pass + FCD(8) – 1.5(11) = 0 through H FED 2.0625 KN + =0 Efy = 0 Fru ( sind) + FJH (Soin B ) +1.5 = 0 IH 8

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