Question

02:05:10 A medical researcher wants to compare the pulse rates of smokers and non-smokers. He believes that the pulse rate for smokers and non-smokers is different and wants to test this claim at the 0.01 level of significance. A sample of 72 smokers has a mean pulse rate of 82, and a sample of 78 non-smokers has a mean pulse rate of 79. The population standard deviation of the pulse rates is known to be 9 for smokers and 10 for non- smokers. Let w be the true mean pulse rate for smokers and be the true mean pulse rate for non-smokers. Step 2 of 5: Compute the value of the test statistic. Round your answer to two decimal places. Answer/How to Enter) 2 Points Keypad < Prev

Answer 1

slu n = 72 x=82 O = 9 where ł,i mean Given n2 = 78 X = 79 pulse rate Smokers 52: mean pulse rate of non-smokers null hypothesis Ho: M, = 42 Ho: The mean pulse rate of and non -&mokers is Against M, 7M₂ Test slătistic use z-test za (54-72) - CM, M2) WN(0,1) ie Smokers sane. HA no 30 + wa (82-795 palcov) n2 Wal (0, 1) - Z=1.93 92 + 10 78 72 level of significance z critical at 0.01 2.576 <Zenit Zeal we is value ie 1.96€2.576 Since mean pulse ie The accept Ho rate Smokers and non-smokers is same and Ho: M,=M2 Ans is Z=1.93