Question

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1.) A 72-kg woman holds a 9-kg package as she stands within an elevator which briefly accelerates upward at a rate of 0.27g. Determine the force R which the elevator floor exerts on her feet and the lifting force L which she exerts on the package during the acceleration interval. If the elevator support cables suddenly and completely fail, what values would R and L acquire?
Your answer is partially correct. Try again. A 72-kg woman holds a 9-kg package as she stands within an elevator which briefly accelerates upward at a rate of 0.27g. Determine the force R which the elevator floor exerts on her feet and the lifting force L which she exerts on the package during the acceleration interval. If the elevator support cables suddenly and completely fail, what values would R and Lacquire? o 9kg 0.279 72kg Answers: While accelerating, (897.0264 -711 112.1283 R= NLE N After the cables fail, R NL 0 N



2.) The quarter-circular hollow tube of circular cross section starts from rest at time t = 0 and rotates about point O in a horizontal plane with a constant counterclockwise angular acceleration = 1.4 rad/s². At what time t will the 0.69-kg particle P slip relative to the tube? The coefficient of static friction between the particle and the tube is μ_s = 0.89.
NOTE: My first incorrect answer is 2.730524156, then my second incorrect answer is 3.673821366,


3.) The small cart of mass m is nudged with negligible velocity from its horizontal position at A onto the parabolic path, which lies in a vertical plane. Neglect friction and show that the cart maintains contact with the path for all values of k. Then calculate the normal force N under the cart if m = 1.7 kg, k = 3.9 m^-1, and x = 2.5 m.

My first incorrect answer is 0.002475903802

Answer 1

1. Since 72 kg woman holds 9 kg package. So, her feet carrying total mass of 72+9=81 kg...

Now, natural acceleration due to gravity 'g' is acting downward & Psueod force of '0.27g' will also be acting downward, so total acceleration will be g+0.27g = 1.27g...

So Reaction on her feet by elevator is

R= 81 x 1.27g =81 x 1.27 x 9.81 = 1009.15 N.