Question

me Information Find the indicated probability using the standard normal distribution. P(Z < -1.08) Click here to view page 1 of the standard normal table. Click here to view page 2 of the standard normal table. P(z< -1.08) = (Round to four decimal places as needed) tes alculator

Answer 1

We have to find

P(Z < -1.08 )

We use a Z table

We look for row headed -1.0 and column headed 0.08

Because -1.08 = -1.0 + (-0.08 )

TABLE 5 Areas of a Standard Normal Distribution (a) Table of Areas to the Left of z z .00 .01 .02 .03 .04 .05 .06 .07 .08 .09 .0003 .0003 .0003 .0005 .0004 .0007 .0010 .0013 .0019 .0005 .0007 .0009 .0013 .0018 .0005 .0008 .0011 .0015 .0021 .0028 .0038 .0051 .0026 -3.4 -3.3 -3.2 -3.1 -3.0 -2.9 -2.8 -2.7 -2.6 -2.5 -2.4 -2.3 -2.2 -2.1 -2.0 .0025 .0034 .0045 ,0068 .0035 .0047 .0062 .0082 .0107 .0139 .0179 .0228 .0089 .0116 .0150 .0192 .0060 .0080 .0104 .0136 .0174 .0222 .0281 .0351 .0436 .0537 .0655 .0793 -1.9 .0287 .0244 .0359 .0307 .0384 .0446 .0548 .0668 .0003 .0003 .0003 .0003 .0003 .0005 .0004 .0004 .0004 .0004 .0006 .0006 .0006 .0006 .0006 .0009 .0009.0008 .0008 .0008 .0013 .0012.0012 0011 .0011 .0018 .0017 .0016 .0016 .0015 .0024 .0023 .0023 .0022 .0021 .0033 .0032.0031 .0030 .0029 .0044 .0043 .0041 .0040 .0039 .0059 .0057 .0055 .0054 .0052 .0078 .0075 .0073 .0071 .0069 .0102 .0099 .0096 .0094 .0091 .0132 .0129.0125.0122 .0119 .0170 .0166 .0162 0158 .0154 .0217 .0212 .0207 0202 .0197 .0274 .0268 .0262 0256 .0250 .0344 .0336 .0329 .0322 .0314 .0427 .0418 .0409 .0401 .0392 .0526 .0516 .0505 .0495 .0485 .0643 .0630 .0618 0606 .0594 .0778 .0764 0749.0735 .0721 .0934 .0918 .0901 .0885 .0869 .1112 .1093 .1075 .1056 .1038 .1314 .1292 .1271 .1251 .1230 .1539 .1515 .1492 .1469 .1446 .1788 1762 .1736 1711 1685 .2061 .2033 .2005 .1977 .1949 .2358 .2327 .2296 .2266 .2236 .2676 .2643 .2611 .2578 .2546 .3015 .2981 .2946 .2912 .2877 .3372 .3336 .3300 .3264 3228 .3745 .3707 3669 .3632 3594 4129 4090 4052 4013 .3974 4522 4483 .4443 .4404 4364 4920 4880 4840 .4801 4761 -1.8 -1.7 -1.6 -1.5 -1.4 -1.3 - 1.2 -1.1 -1.0 .0003 .0002 .0004 .0003 .0005 .0005 .0007 .0007 .0010 .0010 .0014.0014 .0020 .0019 .0027 .0026 .0037 .0036 .0049 .0048 .0066 .0064 .0087 .0084 .0113 .0110 .0146 .0143 .0188 .0183 .0239 0233 .0301 .0294 .0375 .0367 .0465 .0455 .0571 .0559 .0694 .0681 .0838 .0823 .1003 .0985 .1190 .1170 .1401 .1379 .1635 .1611 .1894 .1867 .2177 .2148 .2483 .2451 .2810 .2776 .3156 .3121 .3520 .3483 .3897 .3859 .4286 4247 4681 4641 .0475 .0582 .0708 .0808 .0968 .0951 .0853 .1020 .1151 .1131 .1357 .1210 .1335 .1562 .1814 .1423 -0.9 .1660 .1587 .1841 .2119 .2420 .2743 .1922 .2090 .2389 .2709 .2206 .2514 .3085 .3050 .2843 -0.8 -0.7 -0.6 -0.5 -0.4 -0.3 -0.2 -0.1 -0.0 .3446 .3409 .3192 .3783 .3821 4207 4168 .3557 .3936 4325 4721 4602 .5000 4562 4960 For values of z less than - 3.49, use 0.000 to approximate the area.

P(Z < -1.08 ) = 0.1401

Final answer:-

P(Z < -1.08 ) = 0.1401