Question

Rg 10K 6V battery 10kR3 A + 1-measure: Rth, Vth, Isc 4V Vs + RA R5 3.3K wav gen 2.7K 2- measure vo RL=100 RL=680 RL=1K B RL=2.7K RL=20K

find Rth, Vth, Isc through mesh analysis

Answer 1

To send Rotho ہے . ان fi Raul - Voltage fource is replaced by êts internal resiefance which equal to zonos ere. Shart-circuited R4 RS & Rph i's ( Ri=10k, R2 = 6:24 R3 =105 R = 3.3k , Rs = 2.7k we see, Ra, Rq and R8 are in parallel Their equivalent R2R 4X Re Rst Rs Rz Reg R2 R&RS = 0.78k2

25. 789kr Rey es ein series with the Rz 23 Red R3t Real い cicli = 10-roke Reg" is in parallel weith Rs ار 11 Rega - 10.78 x 10 10+10.78 Rit Rea .' Req = 5-18gler =ube es 5.189 kr * Determination Va of Voi ان سوالات ز ز بيتنا R, n در لار Rz th ISA A R3 22 Zes Iz Iz B darsnian 23.92493 799**)

we aya are havery three mershes In the meth ②, kr. IR TRI +Vsi +(I-Iz) R2=0 & (R+R) I + R3 I - I2 R2 = rs, (6182783) I, - Iz Rza US) T 26.2 I 6.2 Iz =-6 @ In the mesh ③ kv. Rz (Is I) +R$( 12- 13 ) -VS2 - Ra I + (R21 R4) I₂ - Re Iz = Vsa > -6.2 I +9.5 12 -3.3 I3=4 키 In mein , kol 키 - Vsz + RsIz + (13-1₂) Read - Rt Iz + (R4+25) - usz -3.312 + 6 Iz = 6 tu g) Solving ①, ② and I Ij = -5.22 YA, I220.95m4, Iza 1.52A · VT = Voc = VAB = R3 I + R5 Iz = 47052V Vgn= 4.052v

3.3 Is a en To fend Isc Verin Rozlokh , IR Rz=100 R2 = 6-24 n Alltou Isa Terug R4 I3) R5=2-314 Av Iz 53.31 + 525 In loop 10 I prol I, -Inc.)+6+ 6-215-17)=0 26.27 - 6.212 lode =-6 v 12 =4 In logo (12-2) 6.2 + (1 I) 3.3 = (2) In loop 6 -67 7-7 (13-16)+ 3-31 I3-Iz) -- کر ان سی 7-3-372 7 6 Iz 2-7 Isc = 6 I lopp containing toe (al-I) 10 + 27 (Isc-I3)=0

-Ion - 2.13 +12-7160 we got the equaticus. 6.2Iz tolz - 10 Isc 2621 6 -6.21, +9.552 -3.3 Izto. Isc =4 -6 Lul OIy -3.3 Iz + 6 Iz – 2.7 Isc VU -10I + Iz- 2.753 +12.7 Isc=0 Using Cramer's Rale -6.2 +26.2 -6 -6:2 9.5 -3.3 Isc = -3.3 6 6 -2-7 o -10 26-2-62 -6.2 9.5 -3.3 -2-7 G O -3.3 -2.7 12.71 -10 MA Ise = 3970-272 5163.42 * Isc = 0.769mA