Question

Given p(u) 3.6 + ln(u + 3) The 3 starting points you would use would be: Round answers to 4 decimal places as needed. The "new origin" would be at p would have a Select an answer v asymptote of Type your answer as an equation. For example, if the horizontal asymptote is at 3, then type y=3. If the vertical asymptote is at 5, type u=5. The three points you would graph would be: Round answers to 4 decimal places as needed.

Answer 1

Solution P(W) = - 3.6+ ln (U+3) p would have vertical asymptote of u=5 P5) - 3.6 + ln (5+3) 3.6+ enco) -3.6+ 2.07944 - 11 P (5) -1.5205 at u=5