Question

In a trial of 100 patients who received 10-mg doses of a drug dally, 36 reponed headache as a side effect. Use this information to complete parts (a) through (a) below. (a) Obtain a point estimate for the population proportion of patients who received 10-mg doses of a drug daily and reported headache as a side effect. D-(Round to two decimal places as needed.) (b) Verity that the requirements for constructing a confidence interval about p are satisfied Are the requirements for constructing a confidence satisfied? OA. Yes, the requirements for constructing a confidence interval are satisfied B. No, the requirement that the sample size is no more than 5% of the population is not satisfied. OC. No, the requirement that no (1-) is greater than 10 is not satisfied. OD. No, the requirement that each trial be independent is not satisfied (e) Construct a 95% corfidence interval for the population proportion of patients who receive the drug and report headacho as a side effect. The 98% confidence interval is (CD) (Round to the decimal places as needed) (d) Interpret the confidence interval. Which statement below best interprets the interval? O A We are 95% confident that the interval contains the true value of p. OB. There is a 95% chance that the true value of p will fall in the interval, OC. There is a 95% chance that the true value of p will not fall in the interval. OD. We are 95% confident that the interval does not contain the true value of p.

Answer 1

na 100, Number of patients received long dove x= 36, No. of patients reperibed headache P: Propertion of patients receind heachel Ñ = X = 36 .0136 MT 100 10-36 b) :) Each patients side elleed independent of each other. - each trial is indepeplet, o 12 we can cotone nso.ord mi) no cone) 100 +0.36 +0.64 - 23.09 noci) = 23.04 > 10 =) All requirement sanlied in A) Yes, the requirpt for controly condidence intercet are satrlied. The Croa) 1. C.I. far pis (in ficat I-d = 0.95 2=0.0s, 212= Zain = 0.025 - 1.96 from Nama table R. 0.025 (1-2) 0:36+0.64 not 6.2304 10o 0.0023 = 0.048 0.36 + 1.96+ 0.048) 10.36 +0.094 )

(-0.36 -0.094, 0.36 +0.094) (0.266 0.454 0.266 s PS 0, 454 The qst. Ce ar for Pit 0: 266, 0.456) d) (A we are 95 4. Condident that the interveen contains the true value of p.