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5. TRUSS Determine the force in each member of the truss shown below. There is a pin at A and a rocker at E. State whether ea

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free body diagoon C 150N 7 8 m 200N * А D B 8m Ax 125N Ау K omkom, 6mify EmA = 0 (Ey X 12) = (150x87+(200x12 ) + (125x6) 362.By usuing method of joints At joint-A O = 53:13° FAC FAB 15ON Ax 37.5N Efy sino s 37.5 FAC FAC 46• 875 N CT) Efx zo 150 FAC CAt joint-E 362.5N FBE RE To E YRDE Efx =o. FBE =0 Efy =0 RDE RE = 362.5N 362-5N ccomp] RDE At joint-D = 362.5N RDE FBD Fco 20FCD. = 203-125 N [comp] į fx fcd coso FBD FOD 121.875 N (ten] At joint-B 1 foc B: FOD - 121-875N FAB - 121-875N 125N Efy = 0

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