Question

For a Normal distribution with

μ

=

11.4

μ

=

11.4

and

σ

=

2.9

σ

=

2.9

.

What proportion of observations have values less than 17?

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Enter your final answer below, Round to 4 decimal places.

Answer 1

Solution :

P(x < 17) = P[(x - $\mu$ ) / $\sigma$ < (17 - 11.4) / 2.9]

= P(z < 1.9310)

= 0.9733

proportion = 0.9733