Question

The 6061-T6 aluminum shaft is 1 m long and hollow from A to B with loads applied at the midpoint and end of the shaft. Determine the maximum shear stress in the shaft and the angle of twist at A. The outer diameter is 80 mm and the inner diameter is 60 mm in the hollow section. 3 1 4 kNm Z KN

Answer 1

To find the maximum shear stress we have to find the location of maximum torque in the shaft. From torque diagram se know that maximum torque is in the section BC. Then by torsion equation we can find the maximum shear stress in the beam. To find the angle of twist we can say that total twist at A will be the sum of twist in both sections. Please find the attached solution.

Bob. Do = domm Tz Di = 6omm. Tik 4 = 0.5m L = 0.5m T2= 2 kN-m Ti E 4IN-m. Aluminium (Al- 6061976. Taken from internet. G> 24 apa. IP Now. Torque Diagram max torque. 6 kNom. So 2kNm max.shear strey in Beam section Bc. from Torsion equation. GKNim. BC soud shalt т Pp た و ابر D=> 80 mm → 0.08m. R = 40 mm C = IR R = = 0.oym Тр

IR LP Polar moment of inertia. * So. Lp D IP It * 6:08) 32 e 6 (0.04) 6 KN-M (0:08)? 32 max. = 59 683 kN/m2 9-2 emax. - 59.9 MPa NOW Twist at and a OA/B + Oble from Torsion equation. TAB LAB t Tel GIP G.IP) AB BC 6x0.5X1000 2 x 0.5 xlovo Op + 6. Тов), a TP) Be To 566-d), 5(6083-6006)