Question

return *a-- * ++*b; void main() { int x = 6, y = 8; x = func(y, y); printf("x - %d, y = %d\n", x, y); X = sub(&y, &y); printf("x = %d, y = %d\n", x, y); } Ans: PART 3 Writing questions [3 marks) 27. (L.0.3.1) Draw a flowchart to accept two number a and b. Find the sum of all odd numbers between a and b. 28. (L.0.4.3) What is the difference between passing argument by value and by reference? 29. (L.0.4.2) A number is called strong number if sum of the factorial of its digit is equal to number itself. Write a function to check whether a number is strong or not For example: 145 is strong number since 1! + 4! + 5! = 1 + 24 + 120 = 145 Page 3 of 3 code: 1537
help me 27 28 29

Answer 1

Start Input a and b Declare sum to to o Initialize Print Sum (Stop (11220 false true Sum=sumti

28)

• In Call by value, a copy of the variable is passed whereas in Call by reference, a variable itself is passed.
• In Call by value, actual and formal arguments will be created in different memory locations whereas in Call by reference, actual and formal arguments will be created in the same memory location.
• In Call by value method original value is not modified whereas, in Call by reference method, the original value is modified.
• Call by value is the default method in programming languages like C++, PHP, Visual Basic NET, and C# whereas Call by reference is supported only Java language.
• Call by Value, variables are passed using a straightforward method whereas Call by Reference, pointers are required to store the address of variables.

29)

import java.util.*;

class Strong
{
    static int fact(int n)
    {
        int fac=1;
        for(int i=1;i<=n;i++)
        {
            fac=fac*i;
        }
        return fac;
    }
    public static void main(String args[])
    {
        Scanner sc=new Scanner(System.in);
        System.out.println("Enter the number");
        int number=sc.nextInt();
        int copy=number,digit=0,sum=0;
        while(copy>0)
        {
            digit=copy%10;
            sum+=fact(digit);
            copy=copy/10;
        }
        if(sum==number)
        {
            System.out.println("It is a Strong number");
            
        }
        else{
            System.out.println("It is not a Strong number");
        }
    }
}

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