explain why newtons method doesnt work for finding the root of the equation x^3-3x+9=0 if the...

Question

Question

explain why newtons method doesnt work for finding the root of the equation

x^3-3x+9=0

if the initial approximation is chosen to be x1=1

f(x)=x^3-3x+9 -> f'(x)= . if x1=1 then f'(x1)= and the tangent line ued for approximating x2 is . attempting to find x^2 results in trying to by zero

Answer 1

Answer #1

24-349 3+9 = 7 Well consider the function f(x)= x²-3x +9=0 with 2 = 1 Find the root using Newtons method as follows ; XnH =

Answer 2

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