Question

(1 point) A proton collides with a Boron-11 nucleus (Bl). If the proton gets close enough (to within 7.91 fm), it will fuse with the Boron nucleus and produce three helium nuclei (3He“): Pł + B + 3He: (A) How fast would the proton need to be moving at an initial distance of 180 fm to get to 39.5 fm from the Boron nucleus? Assume the proton comes to rest when it reaches 39.5 fm. (B) If the proton has an initial speed of 1.321 x 10 m/s when it is very far away from the Boron nucleus, how close does it get to the Boron nucleus in femtometers (fm)? fm (C) How fast does the proton need to be moving very far away from the Boron nucleus in order to fuse with it? Submit answer

Answer 1

close to Boron nucleus of Proton be come 4ngoro - Grace 1044 Mey for ze2 4766 Ile=163218 10 5810448 106x101x106 When Proton comes Potential energy Here z=5 А 3 4X4 X Change in potential en energy 5x144 X (355 1150) = 0.142 Mey Im on = 0.142x1,6x10-19 x 106 or 3X 106725x10 27 x 2²-2-28810 e = 5.22x106m/s if it goes close to x, (fm) Then, ze? Xm "ple2 or -27 (1.32181 N "T = 78.9.42 fm 저 - r - 27 eta here o distence is given 7.91fm 1.6725x ro 5X1644X106810-19 x 100 7.91 in co2 1.74810' Comisſ = 1.32x10tmis