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مس What is the half-life of the reaction using 2.5 x 10-5 M as the initial...
What volume (mL) of crystal violet stock solution 2.5 x 10-5M is required to prepare a...
What volume (mL) of crystal violet stock solution 2.5 x 10-5M is required to prepare a concentration of 0.00000125 M to a total of 10 mL diluted solution?
2. When the initial (AB2] is 0.255 M, the half-life of the reaction is 13.5 s...
2. When the initial (AB2] is 0.255 M, the half-life of the reaction is 13.5 s and when the initial (AB2] is 0.178 M, the half-life of the reaction is 19.3 s. AB2(g) = A(g) + 2B(9) a. Calculate A[B] when [AB2] is 0.525 M. (5 pts) At Answer: b. Would a 1-step mechanism be plausible for this reaction? Why or why not? (5 pts) c. Given that the reaction is exothermic, predict the sign of AS°(universe). Explain your answer....
2. When the initial (AB2) is 0.255 M, the half-life of the reaction is 13.5 s...
2. When the initial (AB2) is 0.255 M, the half-life of the reaction is 13.5 s and when the initial (AB2) is 0.178 M, the half-life of the reaction is 19.3 s. AB2(g) = A(g) + 2B(g) a. Calculate 18 when [ABa) is 0.525 M. (5 pts) Answer: b. Would a 1-step mechanism be plausible for this reaction? Why or why not? (5 pts) c. Given that the reaction is exothermic, predict the sign of ASⓇ(universe). Explain your answer. (5...
2. When the initial (AB) is 0.255 M, the half-life of the reaction is 13.5 s...
2. When the initial (AB) is 0.255 M, the half-life of the reaction is 13.5 s and when the initial (AB) is 0.178 M, the half-life of the reaction is 19.3 s. AB (g) = A(g) + 2B(A) a. Calculate on when (AB) is 0.525 M. (5 pts) Answer: b. Would a 1-step mechanism be plausible for this reaction? Why or why not? (5 pts) Given that the reaction is exothermie, predict the sign of AS°(universe). Explain your answer. (5...
2. When the initial (AB2] is 0.255 M, the half-life of the reaction is 13.5 s...
2. When the initial (AB2] is 0.255 M, the half-life of the reaction is 13.5 s and when the initial [AB2] is 0.178 M, the half-life of the reaction is 19.3 s. AB2(g) = A(9) + 2B(9) a. Calculate A[B] when [AB] is 0.525 M. (5 pts) ΔΕ Answer: b. Would a 1-step mechanism be plausible for this reaction? Why or why not? (5 pts) c. Given that the reaction is exothermic, predict the sign of ASⓇ(universe). Explain your answer....
The half-life of a reaction, t1/2, is the time it takes for the reactant concentration [A]...
The half-life of a reaction,
t1/2, is the time it takes for the reactant concentration [A] to
decrease by half. For example, after one half-life the
concentration falls from the initial concentration [A]0 to [A]0/2,
after a second half-life to [A]0/4, after a third half-life to
[A]0/8, and so on. on. For a first-order reaction, the half-life is
constant. It depends only on the rate constant k and not on the
reactant concentration. It is expressed as t1/2=0.693k For a...
55) The rate constant for a first-order reaction is 0.54 s-1. What is the half-life of...
55) The rate constant for a first-order reaction is 0.54 s-1. What is the half-life of this reaction if the initial concentration is 0.33 M? 56) The rate constant for a zero-order reaction is 0.54 s-1. What is the half-life of this reaction if the initial concentration is 0.33 M? 57) The reaction that occurs in a Breathalyzer, a device used to determine the alcohol level in a person's bloodstream, is given below. If the rate of appearance of Cr2(SO4)3...
4) What is the half-life of a second order reaction with the rate constant 0.0271 m...
4) What is the half-life of a second order reaction with the rate constant 0.0271 m 's and the initial concentration 0.902M?
The half-life for the reaction below was determined to be 2.14 x 10's at 800 K....
The half-life for the reaction below was determined to be 2.14 x 10's at 800 K. The value of the half-life is independent of the inital concentration of N20 present. The activation energy of the reaction is 259.00 kJ/mol. NO(g) - Nag) +0g) 1st attempt See Periodic Table See Hint What would be the half-life at 1000.32 K?
CH3CHO(g) → CH4(g) + CO(g). Experiment [CH3CHO] (M) initial rate (M/s) 1 0.0300 1.7 x 10−4...
CH3CHO(g) → CH4(g) + CO(g). Experiment [CH3CHO] (M) initial rate (M/s) 1 0.0300 1.7 x 10−4 2 0.0150 8.5 x 10−5 (I) Determine the rate law for this reaction. Make sure you determine the numeric value and units for the rate constant. (II) Determine the half-life for this reaction. (III) If the rate of loss of CH3CHO is 1.7 x 10−4 M/s, then what is the rate of production of methane gas?
2. When the initial (AB2] is 0.255 M, the half-life of the reaction is 13.5 s and when the initial (AB2] is 0.178 M, the half-life of the reaction is 19.3 s. AB2(g) = A(g) + 2B(9) a. Calculate A[B] when [AB2] is 0.525 M. (5 pts) At Answer: b. Would a 1-step mechanism be plausible for this reaction? Why or why not? (5 pts) c. Given that the reaction is exothermic, predict the sign of AS°(universe). Explain your answer....
2. When the initial (AB2) is 0.255 M, the half-life of the reaction is 13.5 s and when the initial (AB2) is 0.178 M, the half-life of the reaction is 19.3 s. AB2(g) = A(g) + 2B(g) a. Calculate 18 when [ABa) is 0.525 M. (5 pts) Answer: b. Would a 1-step mechanism be plausible for this reaction? Why or why not? (5 pts) c. Given that the reaction is exothermic, predict the sign of ASⓇ(universe). Explain your answer. (5...
2. When the initial (AB) is 0.255 M, the half-life of the reaction is 13.5 s and when the initial (AB) is 0.178 M, the half-life of the reaction is 19.3 s. AB (g) = A(g) + 2B(A) a. Calculate on when (AB) is 0.525 M. (5 pts) Answer: b. Would a 1-step mechanism be plausible for this reaction? Why or why not? (5 pts) Given that the reaction is exothermie, predict the sign of AS°(universe). Explain your answer. (5...
2. When the initial (AB2] is 0.255 M, the half-life of the reaction is 13.5 s and when the initial [AB2] is 0.178 M, the half-life of the reaction is 19.3 s. AB2(g) = A(9) + 2B(9) a. Calculate A[B] when [AB] is 0.525 M. (5 pts) ΔΕ Answer: b. Would a 1-step mechanism be plausible for this reaction? Why or why not? (5 pts) c. Given that the reaction is exothermic, predict the sign of ASⓇ(universe). Explain your answer....
The half-life of a reaction,
t1/2, is the time it takes for the reactant concentration [A] to
decrease by half. For example, after one half-life the
concentration falls from the initial concentration [A]0 to [A]0/2,
after a second half-life to [A]0/4, after a third half-life to
[A]0/8, and so on. on. For a first-order reaction, the half-life is
constant. It depends only on the rate constant k and not on the
reactant concentration. It is expressed as t1/2=0.693k For a...
55) The rate constant for a first-order reaction is 0.54 s-1. What is the half-life of this reaction if the initial concentration is 0.33 M? 56) The rate constant for a zero-order reaction is 0.54 s-1. What is the half-life of this reaction if the initial concentration is 0.33 M? 57) The reaction that occurs in a Breathalyzer, a device used to determine the alcohol level in a person's bloodstream, is given below. If the rate of appearance of Cr2(SO4)3...
4) What is the half-life of a second order reaction with the rate constant 0.0271 m 's and the initial concentration 0.902M?
The half-life for the reaction below was determined to be 2.14 x 10's at 800 K. The value of the half-life is independent of the inital concentration of N20 present. The activation energy of the reaction is 259.00 kJ/mol. NO(g) - Nag) +0g) 1st attempt See Periodic Table See Hint What would be the half-life at 1000.32 K?
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