Question

Sve u sve WILL COS() dx over [-6, 6) 9 + sin(x) -0.0619 X Use a calculator to graph fand the antiderivative over the given interval (a, b). y 0.21 f( OOK W W -0.1 -0.27 -ozh 0.2 f FU VA

Answer 1

0.19 0.05 M -6 4/ 6 -4 - -0.05 70.10

This denotes area we are calculating by evaluating the given integral over the interval.

COS X da C0 cosa COS X 9 tsin2x .da da 2 옥 2 E 2 tan't sing 6 Sfa latsin2x Now, Se 9+ sin2x as integrand is 6 an even fmetion d (sinx) 3²+ sin2x O] #2[{tant csing tant (sin bog oo dx = 2 / tant (sinto -0.0619 3 tant (sin atsinza %) = ffres dx = f* fc) de +c =[561] +C = F@)-Fa) +C 3 tant (sina) c=2 tan-isina) CASX q+sina cos a १ J da Cfa) 20 ) Cofane so,

y = cos(x)/(9+ sin? (k)) 0.35 O :y=(1/3:}arctan 0.30 fx)/3) 0.25 + 0.20 -0.15 -0.10 0.05 -6 -5 -4 -2 -1 1 6 x :-0.05 0.10

So, 2nd option for the figures of f(x) and F(x) is correct.

PLEASE RATE.