Question

The expression for the acceleration of a certain simple harmonic oscillator is given by a = – (20 m/s2) cos (2.5t).

a. Calculate the amplitude of the simple harmonic motion.

b. Write an expression for the velocity of the same simple harmonic oscillator

c. Write and expression for the displacement of the same simple harmonic oscillator

Answer 1

a ) a = 6- 20 m/s?) cos(2.5 t) = 90 cos (2.5+) scais acceleration - 20 = A w² w=2.5 rad/ac A = 90 20 m (2.512 Amplitude A: 3.2m b) dr a il dt darasact V S420m/2) Cos(2:54).dk va (-20m/s) sin 2.5 t) 2.5 v=68m/s} sin(2.54) velocity = v=68m/s) sin(isty C) dt smis) sinta.st) at jax = Svat Stemps ficos :icos (2.5t) -8 2.5 displacements > 3.2 Cos(2.5t)