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Question 20 (1 point) In a national survey of 1200 households, 652 preferred cantaloupe to watermelon. Construct a 95% confid
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Answer #1

Given :

Number of sample = n = 1200

Number of success = X = 652

Sample proportion = {\hat{p}} = X/n = 652/1200 = 0.5433

Significance level = \alpha = 1-0.95 = 0.05

At 0.05 significance level the critical value of Z is

ZK12=20.0512=1.96 195.) confidence interval for p : CI= Ⓡ + 2012* $ C1 - p) n =0.5433 + 1.96X10.5433(1-0.5433) 1200 -0.5433+

Answer - option C

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