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Under the action of gravity alone the spring stretched by 3.8 cm with a hanging mass...

Under the action of gravity alone the spring stretched by 3.8 cm with a hanging mass of 200 grams. What are the spring constant “k” and the frequency “f” for this mass?

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Answer #1

- Now 0.2x9.8 0.038 * Seli- given distance ()=0.038 m mass (m) 0.2 kg using Hookes law; we have, (F-k* =) K = F mg - * = 51.

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