Question

2r Problem 3 (20pts). Given 2 concentric loops in free space po = 411 x 10-7 (H/m), The magnetic field of a loop is B = Mo!, assume B1 is uniform inside all the loops. Rz=2002 and 11 = sin(wt) A. Find: a) Self and Mutual Inductance due to 11. b) Current direction for 12 c) Vi and V2 1 a 12 V R2 V2 w

Answer 1

Answer: RŽU, (al Self Inductance due to Ili magnetic flux linked with this coil 0 - LIL It B. 792 • B.A = LE Bina² 1 Mo It a 92 IL 2a Moña 2 mutual Inductance due to In. a > b. II go Mo Il iab? ma B.A = 2 a Mo II.ab? 2 a 2 Moab I Ma 2 a

(b). Current direction for Isi Mutual Inductance is the property of two coil by ventue of which each coil opposes any Changes in Strength of current flowly through others by developing an induced emf. So , Here dign of I will be opposite to the digh of I. I I2, (c) Induced emf. lela dt $ B. A = Molliqaz 28 d (LI) Mota, sinut dt at On Tels Moñow coswt 2 Mona w coswt 2 * Ia= ler RIR) I d (MI) R2 at Igs I Mon 6² d II R 2a at 1 2 a Izs Motb w coswt R2 N2= not be coswt 2 a