Solution :
Mean mu = 0.139
Standard deviation =sq((p*q) /n)
=sq(( 0.139(1-0.139)/1500)
= 0.0089323 = 0.00893
Option C is correct
Please like if it helps me please please
Thank you so much
The 2010 census found that 13.9% of adults in the United States identified themselves as being...
The 2010 census found that 13.9% of adults in the United States identified themselves as being of Hispanic origin. An opinion poll plans to interview 1500 adults at random. What are the mean and standard deviation of the sampling distribution of the proportion of individuals of Hispanic origin for samples of this size? a. Hv=0.861 and Ov=C = 0.00893 Ob. My=0.139 and or=0.00893 OC. Mp=0.139 and op = 0.00893 d. Mp=0.861 and op = 0.00893
The 2010 census found that 13.9% of adults in the United States identified themselves as being of Hispanic origin. An opinion poll plans to interview 1500 adults at random. What are the mean and standard deviation of the sampling distribution of the proportion of individuals of Hispanic origin for samples of this size? a. Hv=0.861 and Ov=C = 0.00893 Ob. My=0.139 and or=0.00893 OC. Mp=0.139 and op = 0.00893 d. Mp=0.861 and op = 0.00893
The 2010 census found that 13.9% of adults in the United States identified themselves as being of Hispanic origin. An opinion poll plans to interview 1500 adults at random. What are the mean and standard deviation of the sampling distribution of the proportion of individuals of Hispanic origin for samples of this size? a. Hv=0.861 and Ov=C = 0.00893 Ob. My=0.139 and or=0.00893 OC. Mp=0.139 and op = 0.00893 d. Mp=0.861 and op = 0.00893
The 2010 census found that 13.9% of adults in the United States identified themselves as being of Hispanic origin. An opinion poll plans to interview 1500 adults at random. Find the probability that such a sample will contain 12% or fewer individuals of Hispanic origin. O a. 0.017 ob.0.013 OC. 0.983 O d. 0.015
3. The 2010 census found that 13.9% of adults in US identified themselves as being of Hispanic origin A poll plans to interview 1500 adults at randam. Find probability that such a sample will contain 1% or fewer people of Hispanic origin Select from below! 01 013 983 OS
1. The 2010 census found that 13.9% of adults in the us identified as Hispanic. A poll plans to interview 1500 adults at random, Cateutate mean and standard deviation of sampling distributien of Hispanics for samples of this sizes Select best answer below: x = 61.00293 u x = .139 0 6 x = .00893 5.139 & 300893 MA=.865 & 5o =, 00893 M 2. A charity receives 20a5 contributions Assume them to be independent and identically distributed with mean2125...