Solution :
Given,
n = 5900 ....... Sample size
x = 1770 .......no. of successes in the sample
Let denotes the sample proportion.
= x/n = 1770/5900 = 0.3
Our aim is to construct 99% confidence interval.
c = 0.99
= 1 - c = 1- 0.99 = 0.01
/2 = 0.005 and 1- /2 = 0.995
Search the probability 0.995 in the Z table and see corresponding z value
= 2.576
Now , the margin of error is given by
E = /2 *
= 2.576 * [ 0.3 *(1 - 0.3)/5900]
= 0.0154
Answer : The margin of error is 0.0154
Option d is correct
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