Question

Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given
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Answer #1

Solution :

Given,

n = 5900 ....... Sample size

x = 1770 .......no. of successes in the sample

Let \hat p denotes the sample proportion.

  \therefore  \hat p = x/n   = 1770/5900 = 0.3

Our aim is to construct 99% confidence interval.

\therefore c = 0.99

\therefore\alpha = 1 - c = 1- 0.99 = 0.01

\therefore  \alpha/2 = 0.005 and 1- \alpha /2 = 0.995

Search the probability 0.995 in the Z table and see corresponding z value

\therefore2012 = 2.576   

Now , the margin of error is given by

E =  Z\alpha/2 *  p(1-P)/n

= 2.576 * \sqrt{} [ 0.3 *(1 - 0.3)/5900]

= 0.0154

Answer : The margin of error is 0.0154

Option d is correct

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