Question

Information Puson TRUSS Find the forces in the members for the truss shown below. Indicate magnitude and sense of the forces in each member le 1 H - QR Question 6 AC- Select one a. 2kc b. 12k c O c. 10k c O d. 9kc

Answer 1

12k 14K 14K 14K 14K 4k D 12k G H I o T OK 0 L 974 M N B 9:44 RA AJE = TK = KL = LM = MN = NB-9.4t +Tano - 9 9 o - Tan (1) 0.45 Z Fy -o: Rot RB - 2+4+4+4+4+4+2 RATRB 24 0 EMAFO: ->-419-4(18)-4(21)-4(36)-4(45)-2(54)+ R2 (54) =0 54 RB = 36+12+108+144 +180 +108 бчRo - 648 RB- 643 54 =12 RB = 12k From equation RA= 12k

Joint A : x Fac --> EFq=0 Fas=0 FAJ RA=12k Eryco: FAC+12=0 FAC = -12K Foc = 12k Compression) Joint ci 2K FAC 45° For Eco Foscos45° FCJ FAC 12K Fersin 45 → E Fg=0 Fac - 2+ Fog Sin45° 12=2+(0.707) Fc5 ܓܝܪ * - 0.707 Fcg 10 Fet = 14.14 K (Tension) → EFR = 0 Foot Fey Cos45º = 0 = -Fog Cos 45' = -(14.14)(0.707) Fco = -10 For = 10 K (compression)

Joint I; →E Fa=0 2K FIH-O H IH Efyzo 2+FIR =0 FIB FIB -2K FIRB = 2k - 2K (compression) * Joint B: FBH si045 Fork IG i 12k 45 Fran B Feu cos 45 B Fon 12k FIRS → EFyzo 12+ Few Sin45 = FIB 12+(0.707) FeH=2 FGH = -10 = -14.14 דפרס Fon - 14.14 kl (compression) > Era 0 Fish Cosus & Fan =0 Fon + (-14.14) (0.707) =0 Fon = 10K (Tension)

Joint N: FAN → EFy co Funzo -> EFx 0 FMN → FBN Z MN FMN = Fron ima = 10K (Tersion)