Question

O topic Chapter Virtual UTAH The Expert X Cech Texthon C 5. Water Flows C Suppose You Preschool - Sch Physics Questi + * //umsc.theexpertta.com/common/Take Tutorialssignment.aspx HW 15: Fluids Begin Date: 6/23/2020 12:01:00 AM - Due Date: 7/29/2020 11:59:00 PM End Date: 8/3/2020 11:59:00 PM (4%) Problem 18: A sump pump (used to drain water from the basement of houses built below the water table) is draining a flooded basement at the rate of 0.85 Ls, with an output pressure of 2.75 * 10 Pa a ent Status aere for adview Status Completed Completed Completed Completed theexpert trong 567.00-15-AIDS 24787. In accordance with Egert TA Tervice copy informatych trictly for Destination of your spert TA Account 50% Part(a) The water enters a hose with a 2.7 cm inside diameter and rises 2.9 m above the pump. What is its pressure at this point, in pascals? You may neglect frictional losses. Grade Summary Deduction 04 Potential 100% sin cos taní) 8 cotan) acos) Ε Submissions 5 6 Attemptsemang atan acotan sinhé ) 1 2 3 per attempt detailed view cosho tanho) cotanh + 0 Degrees O Radians VOLO 7. Completed Completed Completed Completed Completed Completed Completed 4 Sube I give up! Completed Completed Completed Hits: 1 deduction per last Hunts remaining 2 Feedback deduction per feedback 50% Part (b) The hose then goes over the foundation wall, losing 6.55 min height, and widens to 1.3 cm in diameter. What is the pressure now, in pascals? You may neglect frictional losses 9:18 PM

Answer 1

Solno Here Lue have. flow ri Qo7 cm Rate of given. that 0.85 1/3, h = Quam Po = 2.75x105pa S = 1000 rg1 m3 Where 2 Here from the Bernoullis Equation we have * & eV? + fgn = Comtent -ring P- Pressure of the fluid. fa density of fluendo g 9.8 m/s2 velocity of fluid. a) Applying the equation in application here V-> lie have, P₂ + 49 hz = P, & ghi P2= At lg P₂ 2.75 4105 + 1000 x 9,8 x 2.9 Lg (Ah) ; Ah =(2, -22) ou OU P2 = 303420 pa Q that, b> Here Av, so 2 Ain V8 A -> VE 0.85 X10-30X0.01352 > na 1.48457 mis simillanly V₂= 0.85X10 -3/7 X 0.02152 = 0.58531 m/s bernoullis again using equation here, Pra AL1-V3) + fg Chi-ha) = (2.75X105) + 5001 1.484340.5839) + 980 / 2.35) B 299303. 2679 pa] PL