Question

A particle A, with a mass of 205 g, collides with one thin homogeneous metal bar B, with a mass of 1.50 kg. The rod, which can rotate freely about a horizontal shaft through point O at the upper end of the rod, is before the shock at rest. Stuck in the shock particle A on the rod at point P. The distance between points O and P are ? = 0.840 m. Length of the rod ? = 1,050 m. After the impact, the bar rotates (with the particle) 90.0 °, i.e. up to the horizontal position. Determine the speed of particle A just before the impact, ie. determine the speed ?A.

Vy from the side before the shock.

d B L VA V Р A

Answer 1

from d Let 'w be the angular speed just after collision Conservation of Energy mg gx te + Maxgx (MBC / + mad?) w²= mBgL + zmagd [1-5x (1.05)*7 0.2054 (0.8437W= 1-529-821-05 I w²= -> 2 +2 x 0.205x9-8x0.84 5.2 radis =) wa 18.87 = 0.696 Now, Applying conservation of Angular Momention * 0.205 * VA = [1-5*(1.05) dx MAVA Iw MBLES 2 - 0 0.84 +mad? jw +0.205x(0.843]xs.2 » VA 21 m/s Answer