Question

A particle is located at the vector position i = (11 + 4)m and the force acting on it is į = 4ſ + 29 N. What is the torque about the origin ? (14.0 Nm) (-14.0 Nm)k (-14.0 Nm)ſ (-7.00 Nm) (-14.0 Nm)

Answer 1

N'S Force (²)=42+2 position () =( +43 )m Now, torque about the origin is, e = xã (42 +38 ) * (* *43) 16k-a î x 7 = 2 x = 0 =lar Nom. - the Torque about the origin is (14.0) N-m i [ : û x3 =ů: 8x? =-
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P2 = find Vi = 'initial perempuan V2 = final In (final voth) ***- ?; V=584258* 0.001 m3 Pressure (P) slatm = 1 *1013 25 Pa; (final) =10133 5 Pa; for ideal gas, PiY, = P₂ V ₂ SP, = initial presswee Volume .: PV, = Pz V2 -- (101325X 58 x0.001) Or, P,Y, = 5876.85. now, work done for isothermal process is: Ye Y2 W = nRT in AS P, Y, = P₂V₂ on, W = PV, NRT V Or, Wa for ideal (5876.85) in V2 gas. VI "As work done (W) on, 3200=5876.85 x 12 - 32003] V2. - 0.545 V 0.545. Dr, or, V,= 58X0-001 x 0.545 e 33.6 L : now, P2 V2=nRT Or, T = 58 7 6.85 2x 8.314 [As k toe.is ķ-P7B.= °C] C : a) inita al volume is 133.64 e ao V V2 Vi OT, in - V2/vi -e K = 353k b) Temperature is 179.9 °C So, the correct option is (9) 3.3.6L (6) 79.9°C j
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