Question

The figure below shows two masses m,=5.7 kg and m2=2.0 kg. The lower surface is frictionless but the surface between the blocks has an unknown coefficient of static friction us. If a horizontal force of magnitude F=56 N acts on the top block and the bottom block moves along with the top block, what is the magnitude of the static friction force which acts between the two blocks? F4 mi m2 U=0 x Select one 45.60 N 49.75 N 33.16 N 37.31 N 41.45 N

Answer 1

givers 22 564 m, = 5.7kg m2 = 2kg ger ih naseh zlotissa ha Mal uro mi Earn ↑ N2 im its meg F-6s - Mza₂ mzao a, ts M mi (mitm) g $32 m, a, from egno and famia, man 56 2 m2 92+ m, a, a, 92 because frietimal force between surface and mi So, who both m, and Me are is zero

single body. (M₂ tim, ja 56=(2 of 5.7) a 56 = 56 - a 7.7 a = 7.2 mis² from ean ♡ F-ts 2X72 F-14.4 =ts 56 - 14.9=ts 41.6 ats So, friction force force between both blocks is #1.6 N. Ang