Question

(1 point) Archeologists have discovered a sample of ancient Egyptian skulls from 4000 B.C. A sample of 6 Egyptian skull breadths (in mm) from 4000 B.C. is show below. Skull breadth Sample: 137, 134, 138, 127, 130, 131 (a) Calculate the mean and standard deviation for for the data set. Round the mean to 2 decimal places, and the standard deviation to 4 decimal places. 4000 B.C. skull breadths mean: 4000 B.C. skull breadths standard deviation: (b) Using your answers from part (a) and the formula for a 99% confidence interval as presented in lecture, fill in the blanks with the appropriate values for this problem for calculating the confidence interval below. To enter V where x is any number, type sqrt(x). For example, V2 should be written as sqrt(2). 4000 B.C. skull breadths: to (c) Using the formulas from part (b), find the 99% confidence intervals for the mean maximum skull breadths of all Egyptian skulls from 4000 B.C. Round your answer to the nearest hundredth (2 decimal places). 4000 B.C. skull breadths: to

Answer 1

data of skull bread the Given 137,134,138,127,130,131 @ mean (1) = Sum of given data Noi of samples 137 +184 +138+127 +130+131 6 797 6 1320833 mean (M) = 132.833 S.D= Bar & (X; -M2 N-1 (37-132.833)? 7134-132-83317 (138-132-1372 +(127-132 833)2+(130-132 833) +(31-132 833) (6-) 90.833 18.166. 4.2622 Standald deviation (6) = 402622

for mula for confidence interval Mtz M-) mean. 8-) standald deviction n) No of sample Z score for 99% = 2.576.

confidence interval formula will be. 4.2622 132.83 € 2.576 to 132.83+ 2.576 402622 56 confidence interval after solving is (128.3513) to. 137.3153