Question

4. A single phase inverter shown below is using a 1:10 step up transformer which supplies the power to 20W load lamps. If the secondary voltage has rms value of 120Vac and the transformer total winding resistance is 0.8W. Determine the rms input voltage [15 Marks) i. Determine the period and frequency of oscillation for an inverter if the components have the following values: R1=2K, R2=20K, C1=0.04m F & C2=0.05mF [15 Marks) ii. Determine the value of capacitors to be used in an inverter to provide a train of pulses 0.01s side at a repetition rate of 50Hz. Given R1=R2=10K. [20Marks) 120 VAC OU T1 RE 34 91 01

Answer 1

The answer conatins formulas and mathematical clauclations answer attached as images . The given inverter circuit is astable multivibrator. basically multivibrator is an electronic circuit consiting of two cross coupled devices like vaccums tubes or transistors. The detailed explanation given in images.

4. Answer for transformar rms input voltage. 212 vi . I 2 N) N2 ll N2 V2 Il N2 Given values are NIEI N2 =10 Ni= primary winding, N2 = secondary winding No of twing Noi of turns. Vi= primmy input voltage = (findout) V2 = secondary sinput voltage : = 120vac Vi 120 10 = V/? 20 2 ㅗ = %= 12 Vacryms iriput voltage zow, o.sw are powers drawn by the coil seistances. Pi = V, I, 3 V Vi Ri Ri P = vi? Ri= V2 (12 va c]² (12352]? Ri 2ow = 16.97 = 14.42 R2= 169.72 P2 35.99kr 0.8 The given inverter is Astable multi vibrator Let us assume two quasi stable states are there TIF OFF period -0.693, RIE, 20-693x2x5% xo.oyrent T2zon period= 0.693 Rzcz = 0.055 seconds 20 V2² [120482]? 0.8 . =0.6934 20 XJ6 x 0.05x1ā? 0.693 seconds.

period of oscillations are Toti+T2 = 0.693+0.055 Frequency of oscillatiory is = 0.748 seconds ㅗ T 0.748 F- 51:3368 HZ A stable multivibraton diagram : 12V Ry ERI R3 R2 ایہ۔ HE 02 a , A stable multi vibrator has two quasi stable states meaus that it switches from one state to another stake any triggering both are not permonent states. stat2 without TON TOH Asti quasi stable state la Q OFF GLON quasi stable state 2 GiON G2 off ONT Sanyisten borg Voltay - 3V, Covert Veltas : 02V (Silicon)

off traksisha bas voltuge = OV C08) -ve, Collector Voltage a Vcc in this care nealy 12v TE Tit T2= o.ols + Tz ayume T-00)S = 0.02 seconds FI - ㅗ 50 50 Hz = = T T = TITT20.02 seconds T2=0.02-11 0.02 -0.01 -0.01 Series Ti= 0.693 RIC) -0.693 X 10 X 103xCj -0.0) J2=0.693 R2 C2 =0.693X10 X18X (2=0.0) (1=(2= 0.01 =1.44 xób F 0.693 X10 X132 =1.44 MF Jaridato LT - Tati T2 = 0.02 Secedy - 50HZ T 0-02 Faded