Solution :
Given that,
Sample size = n = 95
Z/2 = 1.96
Margin of error = E = Z/2* ( /n)
= 1.96 * (60.6 / 95)
Margin of error = E = 12.19
At 95% confidence interval estimate of the population mean is,
- E < < + E
127.8 - 12.19 < < 127.8 + 12.19
115.61 < < 139.99
(115.61 , 139.99)
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