Question

Constants Part A Calculate the torque magnitude and direction) about point O due to the force F in each of the cases sketched in the figure (Figure 1). In each case, the force F and the rod both lie in the plane of the page, the rod has length 4.00 m, and the force has magnitude 15.0 N You may want to review (Pages 303 - 306) For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Applying a torque. Calculate the magnitude of the torque in case (a). IVO AE ? Nm Submit Request Answer Part B Calculate the magnitude of the torque in case (b) IVO AED ? T = Nm Submit Request Answer Part C Calculate the magnitude of the torque in case (c) AED ? ITI N.m Figure 1 of 1 > Submit Request Answer (b) 20 90.0 120,0 Part D (d) Calculate the magnitude of the torque in case (d) 0 EVO AXO ? 2.00 m (e) ITI = Nm 60.00 Submit Request Answer

Answer 1

Given Length of rod (l) = 4m magnitude og force (F) = 15N concept for solving this problem Torque about any point (O) = Force x peor pendiculas distance from O. 4 Torque = for r

Part A t4m Torque about o (7) = 1584 - 60 Nm anticlockwise bisection 90 IF15 Part B O f will have two component pe vertical componeut (Fu)-FC0530 120 Horizontal component (Fre)= Esin 30' Torque will produce only due to Fv as it is perpendiculas to of rod. aris Fsin3o Fcos3o l=4m Torque = Ecus 30 x 1 - 15 Coso X Y 57.96 Nm (antí clockwise part c Free F COS 39 0 F l=4m for Esin 3o It has two component of forces acting on rod. to F sinzo and Fr = f cosso Torque will act only for vertical component Torque about o = Fax l

T Esin 30 l 15esinzo X 4 30 Nm (antichek urise) part D F = F singo 2m 2 m f 60 . 0 F Costo 2m 2 m force has two components Fu = Esindo and = F custo act only because of Fv about o So, Torque about o (T) = F sin6oxl Torque will T = lsxsin6ox 4 = 51.96 Nm (Clockwise)