A baseball is hit at an angle of 40º above the horizontal with an initial speed...

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A baseball is hit at an angle of 40º above the horizontal with an initial speed...

A baseball is hit at an angle of 40º above the horizontal with an initial speed of v₀=21.2 m/s. At what time does it have a y component of velocity equal to v_y=-6.5 m/s?

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Answer 1

Answer #1

Y component of initial velocity

= 21.2 sin 40° =13.63 m/s

Acceleration = - 9.8 m/s ²

Using,

t = (v-u) /a

t =( -6.5-13.63)/-9.8=2.05 second

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Answer 2

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