A new surgery is successful80% of the time. If the results of7 such surgeries are randomly...
A new surgery is successful80% of the time. If the results of7 such surgeries are randomly sampled, what is the probability that more than 5 of them are successful? Carry your intermediate computations to at least four decimal places, and round your answer to two decimal places.
Homework Answers
This is a case of binomial distribution.
Probability of a successful surgery = 0.8
Total number of surgeries = 7
So, the probability that there are more than 5 successful surgeries out of randomly 7 selected surgeries =
Let X be the random variable denoting the number of successful surgeries.
So, P(X > 5) = P(X = 6) + P(X = 7)
= 7C6 * 0.86 * 0.21+ 7C7 * 0.87 * 0.20
= 0.367 + 0.2097
= 0.5767
So, the probability that more than 5 of them are successful is 0.5767.
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