Question

1 C++ function • Yes this was written by a senior in one of my 300-level classes. • I realized instantly this was HW50 in front of me. double sinLoops (double x) { int i = 7; //this didn't exist. double result = 1/(m+1) // line 3 double pi=3.14; //You need the individual taylor series element. do { double num = x; //these need to be reset each time. double fac 1; //if not they overflow and infinity/infinity is NaN and it exits. for (int counter = 1; counter < (2* i + 1); counter++) { } for (int counter2 = (2 * i + 1); counter2 >= 1; counter2--) { fac *= counter2; } element = num1 * num2 / fac; // line 15 result += element; i++; } while (element > 0.0000001 || element < -0.0000001); ܢܟ • What is the value of "result" in line 3 (if we insert a semicolon to terminate the statement correctly)? • What is calculated in the loop "for (int counter = 1; ...)”? • How will the compiler evaluate line 15? . What value does the function return? Hint: if you say "it doesn't get that far” you will receive full credit. • Unbonus question (for no extra credit): What does this function do?

Language= c++

Answer 1

SOURCE CODE:

*Please follow the comments to better understand the code.

**Please look at the Screenshot below and use this code to copy-paste.

***The code in the below screenshot is neatly indented for better understanding.



This is a very big question.
I have solved all of them. 
Please give me an upvote dear, Much Appreciated.!!



PLEASE FIND THE ANSWERS IN THE COMMENTS:


    double sinLoops(double x) {
        int i=7;
        
        // Question1: Even if we insert a ; at the end, we didn't have any variable m
        // So, we will get an error saying "Cannot resolve symbol 'm' ".
        double result = 1/(m+1); 
        double pi=3.14;
        do {
            double num=x;
            double fac=1;
            /*  Question2: This loop calculates the value of "Twice the value of i"
                It starts from 1 and ends at 2*i +1 
                Example: ==> if i=2, it repeats for: i=1 to 2*2 +1 = 5(Not included)
                    counter=1,2,3,4
                    ==> if i=3, it repeats for: i=1 to 2*3 +1 = 7(Not included)
                    counter=1,2,3,4,5,6
            */
            for(int counter=1; counter<(2*i+1); counter++) {
                
            }
            for(int counter2=(2*i+1); counter2>=1; counter2--) {
                fac *= counter2;
            }
            /* Question3: The evaluation is done like this step by step:
                STEP1: Check the operator precedence of * /
                STEP2: Since, both * and / has the same precedence, evaluate left to right
                STEP3: So, evaluate num1*num2 and then divide (num1*num2) / fac
            */
            element = num1 * num2 / fac;
            result += element;
            i++;
        }while(element > 0.0000001 || element<-0.0000001);
        /*
        Question4:  This Function will NOT return anything. 
                    It results in the compile time error.
                    So, It Does Not Get that far.
         */
    }

/* Question5: What does this function do?
   Answer:    This function is supposed to calculate the sin value of a value.
              Like sin(x)

 */

1 2 public class CounterDemo { double sinLoops(double x) { int i=7; 3 4 5 6 7 8 9 Il Question1: Even if we insert a ; at the end, we didn't have any variable m // So, we will get an error saying "Cannot resolve symbol 'm' ". double result = 1/(m+1); double pi=3.14; do { double num=x; double fac=1; /* Question2: This loop calculates the value of "Twice the value of i" It starts from 1 and ends at 2*i +1 Example: ==> if i=2, it repeats for: i=1 to 2*2 +1 = 5(Not included) counter=1,2,3,4 ==> if i=3, it repeats for: i=1 to 2*3 +1 = 7(Not included) counter=1,2,3,4,5,6 */ for(int counter=1; counter<(2*1+1); counter++) { } 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 a o for(int counter2=(2*1+1); counter2>=1; counter2--) { fac *= counter2; } /* Question3: The evaluation is done like this step by step: STEP1: Check the operator precedence of * / STEP2: Since, both * and / has the same precedence, evaluate left to right STEP3 : So, evaluate num1*num2 and then divide (num1*num2) / fac */ element = num1 * num2 / fac; result += element; i++; }while(element > 0.0000001 || element<-0.0000001); -

33 34 35 }while(element > 0.0000001 || element<-0.0000001); /* Question4: This Function will NOT return anything. It results in the compile time error. So, It Does Not Get that far. 36 37 38 A 39 } 40 نها 41 42 /* Questions: What does this function do? Answer: This function is supposed to calculate the sin value of a value. Like sin(x) 43 44 45

If there are any doubts, comment down here. We are right here to help you. Happy Learning..!! PLEASE give an UPVOTE I Have Put a lot of EFFORT in solving Your Problem. It really Boosts us..!! PLEASE give an UPVOTE I Have Put a lot of EFFORT in solving Your Problem. , It really Boosts us..!!