Question

The figure below shows two masses m₁=3.3 kg and m₂=2.1 kg which are connected by a cable and are in contact with frictionless surfaces as shown. The ramp makes an angle θ=35° with the horizontal and m₂ is acted on by a force of magnitude F=45 N which acts up the ramp. What is the tension in the cable?

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Answer 1

Net force on ma, F W2 quistau Mzg asastan Fret = F = mgg sino = 45 – 2.1 x 9.8 x Sin 35° = 45 - 17.8 - Fret Fnet = 33.2 N This is the net force by which both masses are pulled 35° above the horizontal. Total mass of systems ma m, +m2 = 3.37 2.) 28 = 5.4 kg Also from Newton's 2nd low of motion, mass x acceleration F= a = E m Force a Or - ma I hon acceleration of system = a- Eget 33.2 5.4 6.148m/s² m

ie. both masses are accelerated with 6. 148 m/s² acceleration Tension in the string pulls is equal to force which mass m, Since 801 mass m, have acceleration 6.148 m/s² force m F's ama on mass is 3.3 X 6.148 => F- = 20.3 N which is in So, mass m, is pulled by 20.30 provided by tension sturing so tension in string is T= F = 20.30