Question

PYTHON Im stuck on this problem, PLEASE HELP! and please follow the implementation requirements! THANK YOU!

Implement an efficient python function for the following: def find_Number_of_A11_Possible_Ways(matrix, totalGasAmount): The above function will count all the possible paths from top left cell to bottom right cell of a matrix using exactly totalGasAmount. Each cell of this matrix has a nonnegative number which represents gas amount of that cell. The constraint is that from each cell, you can either move right or move down and you have to use that amount of Gas for moving. Example Input 1: matrix = [ (1, 3, 2, 1], [10, 11, 16, 2], [23, 30, 34, 3] find_Number_of_A11_Possible_Ways (matrix, 12) 1 #1 way to reach destination Explanation: 1 way to reach destination #[right right,right,down, down] and cost is 1+3+2+1+2+3 = 12 Example Input 2: matrix = [ [1, 3, 8, 7] [10, 1, 6, 20), [23, 30, 2, 5] 3 find_Number_of_A11_Possible_Ways (matrix, 25) 2 #2 ways to reach destination

Answer 1

Here is the completed code for this problem. Comments are included, go through it, learn how things work and let me know if you have any doubts or if you need anything to change. If you are satisfied with the solution, please rate the answer. If not, PLEASE let me know before you rate, I’ll help you fix whatever issues. Thanks

Note: Please maintain proper code spacing (indentation), just copy the code part and paste it in your compiler/IDE directly, no modifications required.

#code

# required method
def find_Number_Of_All_Possible_Ways(matrix, totalGasAmount):
    # calling helper method, passing matrix, 0,0 as initial position, and totalGasAmount as gas left
    return helper(matrix, 0, 0, totalGasAmount)


# recursive helper method to assist the above method
def helper(matrix, current_row, current_col, gasLeft):
    # if current_row or current_col went out of range, returning 0 (means no path found)
    if current_row >= len(matrix) or current_col >= len(matrix[current_row]) or gasLeft < 0:
        return 0
    # otherwise subtracting gas amount of current position from gasLeft
    gasLeft -= matrix[current_row][current_col]
    # if this is the last location and gasLeft is 0, we found a path, returning 1 (for current path)
    if current_row == len(matrix) - 1 and current_col == len(matrix[current_row]) - 1 and gasLeft == 0:
        return 1
    # otherwise making two recursive calls to helper method, one going down (moving to next row) and one going right
    # (moving to next column), and returning the sum of values returned by both calls
    return helper(matrix, current_row + 1, current_col, gasLeft) + helper(matrix, current_row, current_col + 1, gasLeft)


# end of helper method


# code for testing, remove if not needed
matrix = [
    [1, 3, 8, 7],
    [10, 1, 6, 20],
    [23, 30, 2, 5]
]

print(find_Number_Of_All_Possible_Ways(matrix, 25))  # 2

#output

2