Question

A commercial building in New Orleans has the following electrical design:

• Lighting System (Demand Factor = 0.75): Indoor lighting = 2.75kW 120V single-phase; Outdoor lighting = 3.50kW 120V single-phase
• Heating System (Demand Factor = 0.70): Electric Furnace - 20,000 btuh 240V single-phase
• Convenience Power (Demand Factor = 0.45): 65 duplex outlets rated at 1.5A 120V single phase
• Include 15% spare circuits for future expansion
• The system has a diversity coefficient of 1.1

Using this information, calculate the gross connected load, gross demand load, and the net demand load for the power distribution system. Make sure to show your work.

Answer 1

Lighting system (D.F = 0.15) Total load = Indoor lighting Indoor lighting toutdoor 2.75kw + 3.50kw = 6:25 KW = . We have 62500. factor($_F)= Max Demand Conneaload - Max-demand = o.fx CL -0-75x6250 - 4687.5W

b) Healing pyetem (D-F70-70) :- We have a blah (british thermal units per hous) Lood- 20,000 bluh = 0.000293071KW .. Load = 20,000+ 0.000393071 KW 5.86kw (2) 5860w. - Mar-demanda D-* C-L 50-775860 4.102kw. = 4102W Convenience power ( D'F 30:45):- → 65 duplex outlets rated at 15A, 1201, 1-0 + 15% spare circuits for future expansion Potal oulkts=2x65=130- Lood = Total outtietox vol apex custent 130 x 1,5 X 120 = 23400 N 15% spare Egcuits = 15% of load 15 100*23400 3510W Now total load: 23400+3510 = 26910 Watts 26.910 kw Max demand= DFX CL (connected (131) totalload) = 0.45x26910 12109.5 Watts total connected load= 6250 +8860+26910 39020 Watts Answer

Große Demand load: sum of All the Max. demands- Groog Demand loads 4687.5+4102 +12109.5 Gross 20899 w Demand load F 20.899 kW. • Answer -> 1.1 Net demand loads - Diversity factor- Sum of the individual M.. Max. Demand of the se plant Große demand load Net demand lood = Net demand load = Gross demand load 1.1 20899 lil 18999W Net demand load. ^ 19kw. Answer.

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