1. Simplify the following Boolean function to
sum-of-product by first finding the essential prime
implicant
F(A, B, C, D) = ∑( 0, 1, 3, 4, 5, 7, 9, 11, 13)
2. Implement the simplified Boolean function in 1. Using NOR gates
only
Solution 1:-
There are 4 prime implicants and 4 essential prime implicants for the given minterms using K-map Boolean expression has been derived and the essential prime implicants are also found.
Essential prime implicants table:-
K-map and Boolean expression:-
Solution 2:-
The function has been constructed using only NOR gates.
1. Simplify the following Boolean function to sum-of-product by first finding the essential prime implicant F(A,...
Given the following boolean expression: F = ABC + ABC + ABC 1. Simplify the expression using only NAND operations. 2. Produce a logic diagram implementing the simplified expression using only 2-input NAND gates. 3. Simplify the expression using only NOR operations. 4. Produce a logic diagram implementing the simplified expression using only 2-input NOR gates.
L ILLLL LLLLLLL LO LLO (7) Boolean Algebra 7 marks (7a) Simplify the following logic function as a sum of products. You may use K-map. 3 marks F = Ā B D + A B D + B C D + C D + ĀB C D (76) 1 mark Implement the simplified logic function F of (7a) as a sum of products with AND and OR gates. Show your steps. You may assume complements of the literals are available....
1. (10 point 1 effort points) Simplify the Boolean function F(A, B,C, D) - 11 (3,4,6,7,1 1,12,13,14,15). a) Generate K-Map of F b) Obtain simplified sum-of-products form of F c) Obtain simplified product-of-sums form of F Note:you should show the final prime implicants you used
1. Simplify the Boolean function (F(A, B, C, D) = ∏(3,4,6,7,11,12,13.14.15) a) Generate K-Map of F b) Obtain simplified sum-of-products form of F c) Obtain simplified product-of-sums form of F Note: you should show the final prime implicants you used
Simplify the following Boolean function F, together with the don’t-care conditions d. Draw a NOR only implementation of the simplified circuit. a. F(x, y, z) = ∑m(0, 1, 4, 5, 6) d(x, y, z) = ∑m (2, 3, 7) b. F(A, B, C, D) = ∑m (5, 6, 7, 12, 14, 15) d(A, B, C, D) = ∑m (3, 9, 11) c. F(A, B, C, D) = ∑m (4, 12, 7, 2, 10) d(A, B, C, D) = ∑m (0,...
2- D (XYZ XYZ +XYZ a. Simplify F using Boolean algebra. b. Draw the logie diagram of the simplified F, using NOR only gates c. Use the most economical multiplexer to realize F d. Simplify (F+D)L using K-map in sum of products so MUX si -l d-
8) Simplify the following Boolean function F, together with the don't care conditions d, and then express the simplified function in sum-of-minterms form: F (A, B, C, D) = 2(4, 12, 7, 2, 10,) d(A, B, C, D) = 2(3, 9, 11, 15) d(A, B, C, D) = 2(0, 6, 8)
4. Simplify the following Boolean function F, together with the don't care conditions d, and then express the simplified function in a. Simplified sum-of-products expression (10 points) b. Simplified Product-of-Sums expression (10 points) F (A,B,C,D)-?m(5,6,7, 12, 14, 15) +zd (39, 11, 15) (Use K-maps for the simplification)
4. Simplify the following Boolean function F, together with the don't care conditions d, and then express the simplified function in a. Simplified sum-of-products expression (10 points) b. Simplified Product-of-Sums expression (10 points) F (A,B,C,D)-m(5,6,7,12,14,15) +d (3,9,11,15) (Use K-maps for the simplification)
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