Use log, 3 % 0.584, log, 5 2 0.788, and log, 7 * 1.095 to approximate...

Question

Question

math algebra

Answer 1

Answer #1

log_b(15/7)

= log_b15 - log_b7 Since, log (m/n) = log m - log n

= log_b 5*3 - log_b 7

= log_b 5 + log_b 3 - log_b 7 Since, log mn = log m + log n

= 0.788 + 0.584 + 1.095 Putting the values

= 2.467 Answer

Answer 2

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