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1. The slender bar AB weighs 60 lb and moves in the vertical plane, with its ends constrained to follow the smooth horizontal
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30lbs . N A 30 bolbs No B => EF. maGX X = 30+ NB = mx agy {fya magy => NA-Go = mx any EMG IGxd => NR X2 CD 36 + NAX 2 Sin30 -ai abi + (dk) x (usin3o1 + u Cos 3oj) Equating i di components i => 2A = 0 - (4 653010 -3.466.& ад j j -> o = a B + (4 Sin 302 IG 60 32-2 X (4) G 12 above m, IG, aGx) Substituting in 0, AGY we get 2 d -4.42 Yad/ clockwise N 68.2 lbs up А NB = - 15.74

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