Question

CLASS ID#: (3) GIVEN: (35 PTS) A slender 9-Ib rod AC can rotate in a vertical plane about a pivot at B. Attached to the rod at C is a spring with a stiffness of k=30 lb/ft and an unstretched length 6 inches. The rod is released from rest in the position shown. FIND: (A) (-10 Pts) The ANGULAR VELOCITY (c) of the rod AC after it has rotated through 90° (B) (-10 pts) The corresponding REACTION at the pivot B after rod AC has rotated through 90° (C) (-15 pts) The MAXIMUM ROTATION of the rod AC. 5 in. B 24 in 14 in.

Answer 1

Total Energy at initial position = Total Energy at o=900 с K from Question sin um A. Wag lb k = 30 1b/ft B 7in 24 in 40=6 in. 4 g=32+2 ft/ ft Bee? De=V142452 14 in A) Augular velocity (wall of the rod de ofter it has notasie though goo from Conservation of Energy + + 2 Ź (14.666-16 506-6) W x 7 12 įk (9.26) +2+J64) g - X → 67-2506 – 5:25) = x0.6736 x W.)? I 32.2 7 Wo)2 = 21.2517 Wo= 4.60gg rad, readsee Answer.

B) Reaction at the pivoted point G ka mwen for Site Bu. By Efnao -> Bu = kre-mwo)2 r a Eku-mo) e 30x(972) - 2.(4.6095) 12 34= 4.035 16 Answer Efyzo > By = W * By=gib Answer c) Maximum rotation of red (0o) 10o = 0 +90 from Conservation of Energy 4 1 2 + {k (31 2 (3-5) = {K (3-51040)? +W (7) sino. 0.1042 (3-5 (oso)2 +5.25 sino. 12 2.0006 +0.9375 0 : 31.999 maximum notation 0o = 121-890 Answer

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