Question

4. Use the focal length you found in (3), complete the table below and check your work in the simulation. Object Distance (p) Image Distance (9) Magnification Nature of the image (Real or (m) Virtual/upright or inverted) 190 cm 120 cm 90 cm 60 cm 30 cm

this is what they gave us

Answer 1

f=+0.6m = +60cm (1) cobject distance P = -190 cm -- 9 f -iso -190 60 lo lo 190-60 60 190 190 X 60 نو = 87.69 cm 141/14,8 ima q 87.69 -0.46 -190 Mature of Image - S Real Because น is positive Inverted Because m is negative () P = -120cm - -120 60 -lot-1 120-60 น 60 120 120 X 60 2 - 120 cm m= 120 = -1 -120 Inverted Nature of Image - Real → qis poenitive negative (iii) p = - 90 cm co q -90 m is 60 90-60 go X60 go you or q = 180 cm

me 180 = -2 -90 Nature of Image q is Real → positive Inverted → m is negative (iv) pa - 60 cm 다. q al- -60 60 clo o 고 60 -108 q = m= 11 -60 Nature of Image Real sq is positive Inverted . m is negative (U) P = -30 cm - I-36 1) -30 60 you you - 11 30-60 60 30 60 x 30 q = - 60 cm m = 60 - + 2 - 30 Nature of Image Virtual q is negative Upright m is positive