Question

Problem #6 (Conversions)

Given the following base 10 decimals

a) 3.75

b) 0.3

c) 89.7

1) Convert to binary, octal and hex, then

2) Convert to NASA Hex float with first 24 bits representing thesigned fraction and the last 8 bits representing thesigned exponent. Scaled as 0.FRACTION x 2^EXPONENT

3) convert a) to scaled integer binary 1 unsinged byte maxium bits,convert b) to scaled integer binary 2 unsinged byte maxium bits,convert c) to scaled integer binary 3 unsinged byte maxium bits,

4) multiply 3) by 1 byte value 7 then shift back to integer and output the result

5) Then convert 2) using IEEE 754 format

Answer 1

SAGAR Page No. Date 89.7 to Binary to to her octal 2189 gg 39 Hay q 8 7 2 220 8. 1 3 89,07 13 18 29/9 51 2 O 89,0? 5916 8 56 8 16 TB 89, 1011001 7 3 2 2 6 2 LG 3 8 8 7 7108333 C 2 2 •71070.556348 द 89.70 2131.0.566314 8 0 89.7, 259.033 70 -0.10ll001) 89.710 101 1001.01011001a

SAGAR Page No. Date Sophie Conversion. a @ 3.75 @ 0:3 © 89. 6 3.7510 to Binary Now whole part to her fraction part 1275 2 13 2 izac 122c 0.7510? O. 46 3,02 12 Aloo fractionfast 0.75 2 5 Hence 3.750 3.016 1 a 0.750 0.12 noo. Un +0.1122 flence 3.75,02 11.lla lille food 38+0.68 368 Hence to octal. fraction part o 1.75 8 6 Scanned wo-750? Orbg CamScanner 3.7.2 3.68 cs

SAGAR Page No Date 6) 0:3 to Binary .3 2 0:30 0.01001100 H0g 6 to octal, 2 to hex 2 e 0 5 2 3 8 214 2 16 12268 S 122cs - 2 2 1 122018 2 S. M 1220 8 OS 1 8. 12201 8 امی 2 2 8 T2=C8 122018 20.2314631 0.310 oscar C C C C case