From the given sample data :
The sample size is , n=10
The sample mean is ,
The sample standard deviation is ,
The null and alternative hypothesis is ,
The test is two-tailed test.
Now , df=degrees of freedom=n-1=10-1=9
The critical values are ,
; From t-table
The rejection rule is ,
Rejec Ho , if t-stat>2.262 or t-stat<-2.262 , otherwise fail to reject Ho.
The test statistic is ,
Decision : Here , t-stat=0.5299 < 2.262
Therefore , fail to reject Ho.
Conclusion : There is sufficient evidence to support the claim that the average chicken weight is 5.5 lbs.
A Hypothesis test 3) Jed raises chickens. He says that the average chicken weight is 5.5...
Use the Roll Verification Data 1) Create a Histogram for the Height data. Convert to feet only to do this.ex 5 feet 3inches is 5+3/12=5.25 2) Calculate the mean, median, standard deviation A Hypothesis test 3) Jed raises chickens. He says that the average chicken weight is 5.5 lbs. Test his claim. A simple random sample, looks like it's from a Normal distribution of Jed's chickens was collected with the following data in pounds: 3.4, 5.8, 6.0.4.2.5.7.7.1.6.3, 6.2.5.1,7.2 (you find...
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The produce manager at a grocery store claims that Granny Smith apples weight a mean of 4 ounces. (FYI: Granny Smith apples are the green ones.) You are a quality control representative and are testing to see if the claim is reasonable or not. The data below represent a POPULATION of scores from which you are to take a SAMPLE. Your sample size will be ten (10) apples. Your task is to take a sample of 10 scores to test...