(a)
The outcome for 6 is 28Option (A) is correct...
problem gives an answer of 25
Ans: The eldest sibling received
$160000
the middle sibling received $92000
the youngest sibling received $80000
@ Q.1. For n = 6 (901) (n) = g(n)) - 115n) 5n-2 ( gou) (6) = 5x6-2 - 28 IC b For n = 10 , 1906) (10) = 5x10 - 2 = 48 For n=110 (906) (V10) = 5x110 -2 = 5770-2 (2) For n=0 (gob) (0) = 5x0 - 2= -2 For n= ç (904) (3) = 5x58-2 27-2= 25-16 (6) For n=n (gof) (n)=5n-2 e 0.00 8 The output for 6 is. 128
can be used instead of letters to represent not as convenient to write as letters, icon Q. 2. I con can be used insteed of letter Mug M, CEL M+M+M = 30 3M = 30 M = 10 Mt C+c=20 Đ 10+20=20 » 2c=10 = C = 5 ctLtL=9 D 5 +22=9 * 2 L=4 + L=2 So, C+ LXM = c + 2x 10 = 5+ 2X10 = 5+20 = 25 option (A Although unconventional because they are Unknown values. Treasing this puzzle as an algebra
Problem gives g res an answer of 125
ig Q3. Let eldest sibling receive $2. youngest sibling receive $y eldest receives 2 times as much as the youngest. n = 24 Here given the 0 so,
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( put in ③ we get n+y+z = 332000 ► 2y + y + z = 332000 → 34 + 2 = 33 2000 (А, brom 2-4 - 12000 D 3-12000 ty put this equation 3y +12000 +y = 332000 44 = 332000-12000 => 4y - 320000 ► y = 320000 = 80000 4 y = 80000 put in ④ we get 3x80000 + z = 33 2000 240000 + 7 = 332000 z= 332000 - 240000 > z= 92000 y ez value put in 0 y = 80000 put in N=24 ► = 2 x 80000 n = 160000 Ans: The eldest sibling received $ 160000 The middle sibling received $ 92000 The youngest Sibling received $ 80000