sts b- ve he 14.15 A graduate student places 0.272 mol of PC13(g) and 8.56 x...
sts b- ve he 14.15 A graduate student places 0.272 mol of PC13(g) and 8.56 x 10-4 mol of PC1s(g) into a 0.718-L flask at a certain temperature. PC13(g) is known to decompose as follows: PC13(g) = PC13(g) + Cl2(g) After the reaction attains equilibrium, the student finds that the flask contains 2.51 x 10-4 mol of Cl2. Calculate the equilibrium constant K, for the reaction at this temperature. a 0.114 b 8.51 x 10-2 C 0.157 d 8.88 X 104 e 2.40 X 104 he ol d.