Question

4.3-1 Figure P4.3-1 shows a scheme for coherent (synchronous) demodulation. Show that this scheme can demodulate the AM signal [A + m(t)cos (24fc1) regardless of the value of A> Figure P.4.3-1 (A + m(t)] cos wet Output Lowpass filter cos, we?

Answer 1

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VIE output Ylt) wewet (wa) Wc → Given Low Pass LA + mct)) aurafet filter zafe the output of Product modulatar vet) VIE) - LA+mit) ) con wel zofet LA + met) ) were wet agwat Cele (Atb) col (4-B) LA + mits] a euinct we wit we zarfet •. 2 quả & HB = - 11 2 lo1 o 11 Atu A tm we awet + mit) Here [A +mit)] {we the awet t we o + m2t)) is the luft off cutt off frequency of Low pass filter is (wc.) het so it will pass frequy and block Higher fregung component (awc). from equation ③ output y(t) lower so the A + mat) 2 А (+) = + 2 mit) to demodulated de term mertage sigual