Question

Determine L-'{F} F(s)= -252-6s+2 (s+2)(8+3) Click here to view the table of Laplace transforms. Click here to view the table of properties of Laplace transforms. L-'{f}=0

Answer 1

B C + 6t2j7 +6+3) we - ; Sot": - Guver, FES) = 6-252-65+2) (5+2)2 (5+3) Let FCs)= А + (5+2) ther (259–65+2) = A(3+2)(5+3) +B(5+3)+c(5+2) Putting 3= -2,-3,0 get respectively -2(-2)2662)+2= B = B = 6 ; -26-3)*—663) +2 =( C 22; 2 = 6A +30 +4C =>6A = 2-33-4C =2-18-8 A = 524) => A=64) FS) -4 (3+2) (5+3) \"{F} = 2+{*23 +2+{estiga} +a+{*} = -4e2+ +6e2+ 2+{s}+2€34 k So, 6 2 + + 5+214 a

[ 7 shift byerty [catre)] = f(y-2)] =-462t +6e2t. t +26 26-34-4e2t + 6+ eat Any it