Question

The voltage in resistor R5 is:

30 R, 21 RS w 512 10 RA ES12V 2012 5,6 V 0,6 V 0.1 v 10V 5,7 V o

Answer 1

Salm Ni 861 RE mon 12v Rişan R₂ RS si yR3 101 ws c B Ry 201 apply KCL at Node A 1,-12 V2 N-V3 + d 6 5 10 V, -120 + 12 V, -12V2 + 300, – 30 V2 = 52V, -12 V2-3093=120 26 V, - 6V2 -15V₂=60 - cling apply KCL at Node B -V, 12 V ~V₂ + M2 t 5 20 5 u V₂-UV, tu tu 12 ~ UV₂=0 gV₂ - UV, -403=0 Ni= (11) g V2-U V3 - CS Scanned with CamScanner 4

apply KCL at Node c V-V2 V2 V₂ - 4 t + 5 2 V₃-2V2 +5V-5V, +V₂ = 0 8V3 – 2V2 -5V, 20. liiij put value of V, from ea. cis to ea.cig & cili 26 ( 9V2-4V3) 6V2-150₂ = 60 u 210V2 –16443 = 240 V2 = 120148213 live los 4 8 V3 – 2V2 -5 (9V2-43). 52 V3 =53V₂ 13 = 53N2 - -(V) put value of V₃ in ea. (iv) 52 1050₂-82853 V2 =120 52 V₂=5.601 valt V2=53x5.601 CS Scanned with CamScanner s

V₂=5.709 valt voltage across Ros Vis 11. Vas = V3 -V2 NR = 5-709-5.601 TURS VRg = 0.108 valt CSScanned with CamScanner